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请问如何获取给定日期范围内的全部日期?

求救:需要获取 2019-12-20 到 2020-3-2 号之间所有日期的列表,结果像这样:[2019-12-20,2019-12-21,2019-12-22,......2020-3-2]。请问怎样才能实现呢?存在跨月跨年的问题。

我现在考虑 通过 new Date 获得当前日期,然后每次加1,但到2019-12-31号再加1,怎么能跳到 2020-1-1 而不能是2019-12-32 呢

最后一次编辑于  2019-10-16
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3 个回答

  • o0o有脾气的酸奶
    o0o有脾气的酸奶
    2019-10-16

    直接写

    function time(time) {

        var date = new Date(time || (new Date().getTime() + 8 * 3600 * 1000));

        return date.toJSON().substr(0, 19).replace('T', ' ');

    }

    var start = '2019-10-01', end = '2022-10-01', st = new Date(start).getTime(), et = new Date(end).getTime(), dates = [], dayTimestamp = 86400 * 1000

    for (var i = 0; i <= (et - st) / dayTimestamp; i++) {

        dates.push(time(st + i * dayTimestamp).split(' ').shift())

    }

    console.log(res)

    =============================================================

    封装

    var RangeDate = {

        dates: [],

        onlyDates: [],

        onlyDate: !1,

        callback: () => { },

        dTimestamp: 86400 * 1000,

        time(time) {

            var date = new Date(time || (new Date().getTime() + 8 * 3600 * 1000));

            return date.toJSON().substr(0, 19).replace('T', ' ');

        },

        getRangeDateA(options) {

            var st = new Date(options.sD).getTime(), et = new Date(options.eD).getTime()

            this.onlyDate = options.onlyDate == !0 ? !0 : !1

            this.callback = options.callback ? options.callback : this.callback

            this.dates = []

            this.onlyDates = []

            for (var i = 0; i <= (et - st) / this.dTimestamp; i++) {

                var tmp = this.time(st + i * this.dTimestamp)

                this.dates.push(tmp)

                this.onlyDates.push(tmp.split(' ').shift())

            }

            return this

        },

        getRangeDate(options) {

            var t = this

            return new Promise((rs, rj) => {

                var d = t.getRangeDateA(options).result()

                this.callback(d)

                rs(d)

            })

        },

        result() {

            return this.onlyDate ? this.onlyDates : this.dates

        }

    }

    ==================================================

    使用例子

    链式风格

    console.log(RangeDate.getRangeDateA({

            sD: '2019-10-01',

            eD: '2022-10-01',

            onlyDate: !0

        }).result()

    )


    callback风格:

    RangeDate.getRangeDate({

        sD: '2019-10-01',

        eD: '2022-10-01',

        onlyDate: !0,

        callback: function (res) {

            console.log(res)

        }

    })


    Promise风格

    RangeDate.getRangeDate({

        sD: '2019-10-01',

        eD: '2022-10-01',

        onlyDate: !0

    }).then(res => {

        console.log(res)

    })


    async / await 风格

    console.log(await RangeDate.getRangeDate({

        sD: '2019-10-01',

        eD: '2022-10-01',

        onlyDate: !0

        })

    )


    2019-10-16
    有用 2
    回复 7
    查看更多(2)
  • 刁_Kyle
    刁_Kyle
    2019-10-16
    获取当时毫秒,然后++1天的毫秒,然后再转换格式
    2019-10-16
    有用 2
    回复
  • 肖宇
    肖宇
    2019-10-16
    // startDate: 计划开始时间; endDate:计划结束时间;dayLength:每隔几天,0-代表每天,1-代表日期间隔一天
    const getDates = (startDate, endDate, dayLength) => {
      let result = [];
      result.push(startDate);
      for (let i = 0; ; i++) {
        let getDate = getTargetDate(startDate, dayLength);
        startDate = getDate;
        if (getDate <= endDate) {
          result.push(getDate);
        } else {
          break;
        }
      }
      return result;
    }
    // startDate: 开始时间;dayLength:每隔几天,0-代表获取每天,1-代表日期间隔一天
    const getTargetDate = (date, dayLength) => {
      dayLength = dayLength + 1;
      let tempDate = new Date(date);
      tempDate.setDate(tempDate.getDate() + dayLength);
      let year = tempDate.getFullYear();
      let month = tempDate.getMonth() + 1 < 10 ? "0" + (tempDate.getMonth() + 1) : tempDate.getMonth() + 1;
      let day = tempDate.getDate() < 10 ? "0" + tempDate.getDate() : tempDate.getDate();
      return year + "-" + month + "-" + day;
    }
    module.exports = {
      getDates: getDates
    }
    console.log(util.getDates("2019-12-20","2020-03-02",0));


    网上找了这个轮子,封装了一下,测试可用

    2019-10-16
    有用 1
    回复 1
    • 匏瓜
      匏瓜
      2019-10-16
      多谢,我先消化一下代码
      2019-10-16
      回复
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