我之前测试的，不管用
let list1 = ['a', 'b','c' ];
let list2 = ['a', 'b'];
let same = [];
let tet =[]
for (let i = 0; i < list1.length; i++) {
for (let p = 0; p < list1.length; p++) {
if (list1[i]!=list2[p]) {
same.push(list1[i])
}else{
tet.push(list1[i])
}
}
请教一下，如何运算得出相同元素为a,b,不同的元素c
想获得比较数组比较好用的方法
数组
取并集
let a=new Set([1,2,3,4,5]);
let b=new Set([1,2,3,4,5,6,7,8,9]);
let arr = Array.from(new Set([...a, ...b]));
console.log('arr',arr);
取交集
let a=new Set([1,2,3,4,5]);
let b=new Set([1,2,3,4,5,6,7,8,9]);
let arr = Array.from(new Set([...b].filter(x => a.has(x))));
取差集
let a=new Set([1,2,3,4,5]);
let b=new Set([1,2,3,4,5,6,7,8,9]);
let arr = Array.from(new Set([...b].filter(x => !a.has(x))));
console.log('arr',arr);
数组对象
取交集
let a=[{id:1,a:123,b:1234},{id:2,a:123,b:1234}];
let b=[{id:1,a:123,b:1234},{id:2,a:123,b:1234},{id:3,a:123,b:1234},{id:4,a:123,b:1234}];
let arr = [...b].filter(x => [...a].some(y => y.id === x.id));
console.log('arr',arr)
取差集
let a=[{id:1,a:123,b:1234},{id:2,a:123,b:1234}];
let b=[{id:1,a:123,b:1234},{id:2,a:123,b:1234},{id:3,a:123,b:1234},{id:4,a:123,b:1234}];
let arr = [...b].filter(x => [...a].every(y => y.id !== x.id));
console.log('arr',arr);
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