将通过wx.chooseimage得到的图片链接传参到珊瑚图片内容安全去识别，结果返回是{参数值错误}？？？

返回的参数为：

相关复现代码：

wx.chooseImage({
      count: 1,
      sizeType: ['original'], 
      sourceType: ['camera'], 
      success: res => {
        wx.serviceMarket.invokeService({
          service: 'wxee446d7507c68b11',
          api: 'imgSecCheck',
          data: {
            "Action": "ImageModeration",
            "Scenes": ["PORN", "POLITICS", "TERRORISM", "TEXT"],
            "ImageUrl": res.tempFilePaths[0],
            "ImageBase64": "",
            "Config": "",
            "Extra": ""
          },
        }).then(res => {
          console.log(res)
          if (res.data.Response.Suggestion!="PASS"){
            wx.showModal({
              title: '警告',
              content: '图片内容不健康，创建失败！'
            })
          }
        })
     }
})