todos:[{
_id: '001',
tags: ['a', 'b', 'c', 'd']
}, {
_id: '002',
tags: ['c', 'e', 'd', 'f']
}, {
_id: '003',
tags: ['c', 'r', 'g', 'h']
}, {
_id: '004',
tags: ['c', 'z', 'd', 'y']
}]
// 如何查询 tags 中包含 ['c','d'] 的记录
db.collection('todos').where({
tags: 包含['c', 'd']
}).get()
求教，如何查询 tags 中包含 ['c','d'] 的记录，谢谢！
只需要包含c和的话
let todos = [{
_id: '001',
tags: ['a', 'b', 'c', 'd'],
judge:0
}, {
_id: '002',
tags: ['c', 'e', 'd', 'f'],
judge:0
}, {
_id: '003',
tags: ['c', 'r', 'g', 'h'],
judge:0
}, {
_id: '004',
tags: ['c', 'z', 'd', 'y'],
judge:0
}]
for (let i=0;i<todos.length;i++) {
for (let j=0;j<todos[i].tags.length;j++) {
if (todos[i].tags[j]=='c'||todos[i].tags[j]=='d') {
todos[i].judge+=1
}
}
if (todos[i].judge==2) {
console.log(true)
}
}
console.log(todos)