<?php

  header("Content-Type:application/json;charset=UTF-8");

  $uphonenumber = $_POST['phonenumber'];//post获得手机号码表单值

$json = '';

$data = array();

    include('init.php');//链接数据库

//$sql = "SELECT * FROM yffice_project where uphonenumber = $uphonenumber";

$sql = "SELECT * FROM yffice_project where uphonenumber = $uphonenumber";

mysql_query("set names utf8");

$result = mysql_query($sql);//执行sql

if($result){

//echo "查询成功";

while ($row = mysql_fetch_array($result))

{

$data["uid"]=$row["uid"];

$data["pcontent"]=$row["pcontent"];

$data["ppic"]=explode(",",$row["ppic"]);

$data["pdate"]=$row["pdate"];

$data["pweek"]=$row["pweek"];

$data["pweather"]=$row["pweather"];

}

$json=json_encode($data);

echo $json;

}else{

echo "查询失败";

}

mysql_close();//关闭数据库

?>

贴一下我的php代码

没用 我在想是不是我返回是对象不是数组的原因

<image src='{{logs.ppic[item]}}'></image>

这是返回的数据 item.pcontent和item.ppic都是取不到的

我ppic里面是个对象数组

怎么会出不来呢，你看看你的代码写对了吗

<view class="container">

    <view wx:for='{{logs}}'>

        <view>{{item.pcontent}}</view>

        <view>

            <image src='{{item.ppic}}'></image>

        </view>

    </view>

</view>

你这样写我连pcontent都显示不出了

把for循环放在 hidden条件的那个view上 还有for循环的默认名称就是item

<view wx:for='{{logs}}'>

    <view>{{item.pcontent}}</view>

    <view><images src='{{item.ppic}}'></images></view>

</view>