文件是通过writeFileSync生成的，用户通过小程序写一个txt文件，然后小程序需要把用户编辑好的txt上传服务器，writeFileSync生成的文件uploadFile时直接就是空的，shareFileMessage时直接报错无效的path，就很奇怪要怎么把writeFileSync生成的本地文件上传和分享？
相关问题
相关文档
- wx.shareFileMessage: 小程序/开发/API/转发/wx.shareFileMessage
- wx.shareFileMessage#参数: 小程序/开发/API/转发/wx.shareFileMessage
- wx.shareFileMessage#功能描述: 小程序/开发/API/转发/wx.shareFileMessage
- wx.shareFileMessage#示例代码: 小程序/开发/API/转发/wx.shareFileMessage
- wx.onLocalServiceResolveFail: 小程序/开发/API/网络/mDNS/wx.onLocalServiceResolveFail
贴代码看看。
let id = e.currentTarget.id.replace("H","")
let dt = this.data.scrs[id].script
let nm = this.data.scrs[id].sname
wx.shareFileMessage({
filePath: dt,
fileName: nm,
})
},
let tfp = wx.env.USER_DATA_PATH + app.fpLocalScript + "/"
try{
fs.accessSync(tfp)
}catch{
fs.mkdirSync(tfp, false)
}
let fp = app.getSafeScriptPath(fs, tfp, this.data.name)
fs.writeFileSync(fp,"","utf-8")
let ss = wx.getStorageSync(app.stkScripts) ?? []
if(!ss.push) ss = []
ss.push(fp)
wx.setStorageSync(app.stkScripts, ss)
wx.navigateBack()