let url = 'https://api.mch.weixin.qq.com/papay/entrustweb?appid=wxxxxxxxxxxxxxx&contract_code=xxxxxxxxxxxxx&contract_display_account=xxxxxxxxxxxxx&mch_id=xxxxxxxxxxxxx¬ify_url=xxxxxxxxxxxxx&plan_id=xxxxxxxxxxxxx&request_serial=xxxxxxxxxxxxx&return_app=3×tamp=1763715334&version=1.0&sign=xxxxxxxxxxxxx'
let req = new wxopensdk.OpenWebViewReq
req.url = url
let context = getContext(this) as common.UIAbilityContext
WXApi.sendReq(context, req)
(由于保密原因,参数只能xxx)我的代码是这样写的,调用后跳转到了微信,但是微信没有跳转网页,是我哪里写的不对吗

你好,报错提示什么呢?