小程序用shortLink跳转报错,为啥提示还要appId?
navminiprogram:function(){ wx.navigateToMiniProgram({ shortLink: "#小程序://群接龙/rR2o6K6t2LwTkSu", success(res){ console.log("success"); }, fail(err){ console.log(err); } }); 结果报错: {errMsg:"navigateToMiniProgram:fail parameter error: parameter.appId should be String instead of Undefined;"}