- iOS微信分享问题?"由于应用安全校验不通过,无法完成微信分享"
WXAPI-SDK版本:iOS 1.8.7.1 设备系统:iOS 13.4 设备型号:7Plus 微信app版本:7.0.10 appID:wxe2add7049f436c20 问题描述:集成了新版SDK,配置了Universallink(已测试正常使用,微信后台也配置了域名/ext/,如果错误只会提示“应用Universallink不正确”),一切配置都正确(包括AppID)。操作流程:app调起微信,进入app校验读条,返回app,再跳微信,提示“由于应用安全校验不通过,无法完成微信分享”。未连续调用sendReq ,微信日志已经上传,微信号wxid_yb4um8x8ltja21,上传时间2020.5.11 14:05。另外,以下方法有回调,return ture。 func application(_ app: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey: Any] = [:]) -> Bool { return WXApi.handleOpen(url, delegate: self) } func application(_ application: UIApplication, continue userActivity: NSUserActivity, restorationHandler: @escaping ([UIUserActivityRestoring]?) -> Void) -> Bool { return WXApi.handleOpenUniversalLink(userActivity, delegate: self) } 控制台log Step: 0 Step: 1 Step: 2 WeChatSDK:wxlog:set property list Step: 3 WeChatSDK:wxlog:launch app with ul only success Step: 4 WeChatSDK:wxlog:Successfully starting WeChat with the universal link. Step: 5 WeChatSDK:wxlog:WXCheckULStepResult[success: 1, errorInfo: Universal Link check passed. The application is launched by WeChat via Universal Link, suggestion: ] Step: 6 WeChatSDK:wxlog:WXCheckULStepResult[success: 1, errorInfo: All Check Passed!, suggestion: ] WeChatSDK:wxlog:launch app with ul only success WeChatSDK:wxlog:openURL success:1, url:https://help.wechat.com/app/wxe2add7049f436c20/refreshTokenFail/?bundleID=com.zhonglejia.everyenjoy&isShare=1&errCode=5&errMsg=context%5Bb37fe006056c707d911139838bd2d6f86ac2bbfd-2413ea9af24091a487beec05be915687137352cc%5D%20not%20match&wechat_app_bundleId=com.zhonglejia.everyenjoy [图片] 麻烦工作人员帮忙看看问题。
2020-05-11 - 微信分享 显示由于安全校验未通过
https://developers.weixin.qq.com/doc/oplatform/Mobile_App/Share_and_Favorites/iOS.html Universal Links校验正确,appid校验正确。微信开放平台自检函数走完了,没报错,但是一直报由于安全校验未通过,麻烦尽快回复我,很急
2021-08-18