我需要从我们的app跳转到微信然后打开一个URL，通过weixin://dl/business/?ticket=调用提示我bad_param，这个该怎么解决 调用代码如下 OpenWebviewReq *req = [[OpenWebviewReq alloc] init];     req.url = @"weixin://dl/business/?ticket=tdfd2ba5686833d7ecdee6e11c86f7f64#wechat_redi";     [WXApi sendReq:req completion:^(BOOL success) {     }]; [图片]

WXOpenBusinessWebViewReq *req = [[WXOpenBusinessWebViewReq alloc] init]; req.businessType = 12; //固定值 NSMutableDictionary *queryInfoDic = [NSMutableDictionary dictionary]; [queryInfoDic cdf_safeSetObject:preEntrustwebId forKey:@"pre_entrustweb_id"]; req.queryInfoDic = queryInfoDic; WEAKSELF [[WXPayClient shareInstance] sendReq:req completion:^(BOOL success) { if (!success) { [weakSelf showToastWithMessage:@"签约失败"]; } }]; ⁣iOS开发微信签约，跳转到微信app，微信提示other，该怎么解决？ 微信appid:⁣wx4e4a2790403cacce 返回的参数pre_entrustweb_id：ab93eb45c904a90ca32e2c46f5b6f9a94bf56a1af29db474bbf0252b1570c7371616738962o8espq67qbUaFcuSiKwiYCJvyYkes4ix