我想通过在微信公众号中菜单做一个扫码功能，然后根据扫码不同的内容，跳转到特定的网址，单纯的文字回复不直观，请教一下大佬应该如何做

[图片] 查看 nginx 日志 1.69.101.237 - - [14/Jan/2024:19:03:40 +0800] "GET /wx/server?signature=d33b49ec8b29c1347f7d13b4ccb286c166ad1b57&echostr=6226182828642779037×tamp=1705230220&nonce=1276533680 HTTP/1.0" 301 0 "-" "Mozilla/4.0" "-" 81.69.101.237 - - [14/Jan/2024:19:03:43 +0800] "GET /wx/server?signature=05a5fc360e4cf0afa4ca4eb798289a824fab4e5c&echostr=838890905131794351×tamp=1705230223&nonce=1869353397 HTTP/1.0" 301 0 "-" "Mozilla/4.0" "-" 81.69.101.237 - - [14/Jan/2024:19:09:05 +0800] "GET /wx/server?signature=74e053d4fb396f71074a36a12a43fd943743c05b&echostr=8431048218563309817×tamp=1705230545&nonce=1508246632 HTTP/1.0" 301 0 "-" "Mozilla/4.0" "-" 81.69.101.237 - - [14/Jan/2024:19:10:08 +0800] "GET /wx/server?signature=e9bc1147af4922bd2b0e9e5898e77a208d549d6d&echostr=6135013566274064849×tamp=1705230608&nonce=380386777 HTTP/1.0" 301 0 "-" "Mozilla/4.0" "-  返回的状态码是 301 浏览器直接请求是 状态正常 ```nginx 42.236.252.160 - - [14/Jan/2024:19:03:36 +0800] "GET /wx/server/?signature=e4fb355c388f05e1910a78cefa496da9deadec00&echostr=2053238259179583870×tamp=1705228412&nonce=155961277 HTTP/1.1" 200 19 "-" "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_15_7) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/120.0.0.0 Safari/537.36" "-" ``` 不明白什么原因？ chrome 浏览器是 mac 最新版本 微信公众号平台返回的码 {"base_resp":{"ret":200304,"err_msg":"default"}} appid wx1590f72c3e178646