- uniapp(ios)插件开发实现通过app拉取小程序功能,拉取失败
有没有开发过痛过集成微信SDK实现app拉取小程序的大哥可以帮忙看看啊 以下代码为uniapp(ios)插件开发代码 #import "TestModule.h" #import "WXApiManager.h" #import "WXApi.h" #import "WXApiObject.h" #import "WXApiRequestHandler.h" @implementation TestModule // 通过宏 UNI_EXPORT_METHOD_SYNC 将同步方法暴露给 js 端 UNI_EXPORT_METHOD_SYNC(@selector(testSyncFunc:)) /// 同步方法(注:同步方法会在 js 线程执行) /// @param options js 端调用方法时传递的参数 - (NSString *)testSyncFunc:(NSDictionary *)options { // options 为 js 端调用此方法时传递的参数 NSLog(@"%@",options); //拉起微信小程序 NSString *path = [NSString stringWithFormat:@""]; WXMiniProgramType type = (WXMiniProgramType)[@"0" integerValue]; [WXApiRequestHandler launchMiniProgramWithUserName:@"" path:path type:type]; // 同步返回参数给 js 端 注:只支持返回 String 或 NSDictionary (map) 类型 return @"success"; } @end #import "WXApiRequestHandler.h" #import "WXApi.h" @implementation WXApiRequestHandler #pragma mark - Public Methods + (BOOL)launchMiniProgramWithUserName:(NSString *)userName path:(NSString *)path type:(WXMiniProgramType)miniProgramType { WXLaunchMiniProgramReq *launchMiniProgramReq = [WXLaunchMiniProgramReq object]; launchMiniProgramReq.userName = userName; //拉起的小程序的username launchMiniProgramReq.path = path; ////拉起小程序页面的可带参路径,不填默认拉起小程序首页,对于小游戏,可以只传入 query 部分,来实现传参效果,如:传入 "?foo=bar"。 launchMiniProgramReq.miniProgramType = miniProgramType; //拉起小程序的类型 return [WXApi sendReq:launchMiniProgramReq]; } @end 最后报错:com.taobao.weex.bridge (9): "+[WXApi sendReq:]: unrecognized selector sent to class 0x102ddbf28"
2021-10-21 - 开发uniapp插件(ios)怎么调用微信api?
插件中调用微信api实现app拉起小程序功能报错。 +[WXApi sendReq:]: unrecognized selector sent to class 0x1021f7f28'
2021-10-19